Top seeded Sai Praneeth, who enjoyed a flying start to the tournament eventually suffered a crushing defeat to Hong Kong's Cheuk Yiu Lee. The Indian, apart from very brief moments was completely outplayed as he lost the quarterfinal tie in straight games.
India's Sai Praneeth will take on Hong Kong's Lee Cheuk Yiu in the quarterfinal of the 2018 Australian Open.
The 2018 Australian Open, also known as, the Crown Group Australian Open is a badminton tournament that will take place in Sydney, Australia. All the matches of the tournament are being played at the Sydney Olympic Park in Australia. The winner of the tournament will be given seven thousand points, while the runner-up will be given five thousand, nine hundred and fifty.
Sai Praneeth is currently the top seed of the Australian open after H.S. Prannoy withdrew. Praneeth has been on a good run in the competition so far, defeating Israel's Zilberman and Indonesia's Maulana in straight games, in the first and second round respectively.
Praneeth's opponent, Lee Cheuk Yiu is the seventh seed for the tournament. Lee defeated Indian Lakshya Sen in the first round before overcoming Malaysian Cheam J.W. in the second round.
Praneeth will be looking to continue his great form in 2018 by winning the tournament.