Joseph Holmes will meet Junyong Park on the preliminary card of UFC Fight Night 213: Kattar vs. Allen.
The South Korean fighter will be making his seventh appearance in the UFC, while his American counterpart Joseph Holmes will make the walk for the third time in the promotion.
Junyong Park stands at 6'0" (182.8 cm) and has a reach of 73 inches. He last weighed in at 185.5 pounds in his fight against Eryk Anders, which he won via split decision. His UFC record is 4-2 and his overall MMA record is 13-5.
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'The Iron Turtle' made his UFC debut against Anthony Hernandez at UFC Fight Night 157. He lost the fight via submission by way of an anaconda choke in the second round.
After his debut loss, Park racked up three wins before losing to Gregory Rodrigues at UFC Fight Night 196. He lost the fight via KO in the second round.
Joseph 'Ugly Man' Holmes, meanwhile, stands at 6'4" (193 cm) and has a reach of 80 inches. He last weighed in at 185 pounds against Alen Amedovski at UFC Fight Night 206. He won the fight via rear-naked choke in the first round. He has fought twice in the UFC with an MMA record of 1-1. Holmes' overall MMA record is 8-2.
'Ugly Man' made his UFC debut against Jamie Pickett at UFC Vegas 46. He lost via unanimous decision.
Junyong Park vs. Joseph Holmes: Who takes the win?
With 18 fights on his record, Junyong Park is the more experienced fighter coming into the bout. In 18 fights, he has four first-round finishes by KO, three submission victories and six decision wins.
Joseph Holmes has had 10 fights to date with only two losses. He has also had a 100% finishing rate in all his wins. He has a reach advantage of seven inches over his South Korean counterpart. He has five first-round finishes in his career.
At this point, it is difficult to call the winner for this bout, though betting odds have the 'The Iron Turtle' as the slight favorite (-200) against the American.
The bout will take place on the preliminary card of UFC Fight Night 213: Kattar vs. Allen on October 29.